Since we started to go to school, teachers have been asking the area of this and that – usually shapes and polygons. Common formulas for getting the area are as follows: For the area of a right triangle, it is given by the equation A=1/2(B x H), which implies that the area is equal to half the product of the base and the height of the triangle. |
However, this formula applies only to right triangles since a right triangle always has its height. With this problem, Heron, a famous mathematician thought of a general formula in getting the area of any triangle. His discovery was named after him. It is now known as the Heron’s formula. His formula is given by the mathematical statement: √(s (s-a) (s-b) (s-c)). This statement implies that the area of any generalized triangle can be solved by getting the square root of the product of the four terms. In the said equation, “a, b, c” stand for the sides of the triangle while s is given by half the sum of all the sides or s=1/2 (a+b+c).
In addition, quadrilaterals are amongst the most common polygons wherein its area is always determined. For a square, its area is just the product of the two sides or its side squared, which is in mathematical terms, A=s2. Also, the area of any parallelogram is given by A= B x h. The height of a parallelogram can be solved by drawing a vertical line up to the base and solving by using the Pythagorean formula.
Moreover, the Pythagorean formula is a formula for right triangles. This was formulated by Pythagoras. He was trying to relate the sides of any right triangle to its longest side or the hypotenuse. In general, the Pythagorean formula is C2=A2 + B2 where C is the longest side and B and C are the other sides of the right triangle.
For you to be more aware of formulas that you can use in school or even in your everyday life, visit MathComplete.Com. This site will give you things especially formulas that can help you.
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